Looking dimensions of a quantity?
Dimension of style?
Dimension of power?
Dimensions of energy?
Dimension of impulse?
Dimensions of momentum?
Assuming that some unknown formula X High School student, unless length (m), mass (kg), time (s), velocity (m / s), acceleration (m / s 2), wide (2 m) and volume ( m 3) are assumed to be known, following a decrease in the amount of Physics modest dimensions.
Here is the format:
Formula ---> Unit -> Dimension
and remember:
mass -> kg -> M (from M ass time ..!?! & do kliru M ether ..!)
length -> m -> L (L ength of time ...!?!)
time -> s -> T (from T ime time ...!)
Style
mass x acceleration -> (kg) (m / s 2) -> MLT - 2
Massa Type
mass / volume -> (kg) / (m 3) -> ML -3
Energy
mass x acceleration of gravity x height -> (kg) (m / s 2) (m) -> ML 2 T - 2
Pressure
force / area ---> (kg) (m / s 2) / m 2 -> ML -1 T -2
Business
force x displacement -> (kg) (m / s 2) (m) -> ML 2 T -2
Momentum
mass x velocity -> (kg) (m / s) -> MLT -1
Impulse
force x time interval -> (kg) (m / s 2) (s) -> MLT -1
Power
Effort / time -> (kg) (m / s 2) (m) / (s) -> ML 2 T -3
Weight
mass x acceleration due to gravity -> (kg) (m / s 2) -> MLT -2
Specific gravity
weight / volume -> (kg) (m / s 2) / (m 3) -> ML -2 T -2
Some have the same amount of dimensions, such as Enterprise and Energy, Style and weight, impulse and momentum.
For a slightly more complicated matter usually displayed formula, the brain-tweaking live, move left and right, up and down, insert the new unit is converted to a dimension.
Just a Sample:
Formula given the force of gravity between two objects as follows
by F is the force (Newton) m 1 and m 2 are the masses of the two pieces of the object (kg), r is the distance between the two objects (m) and G is a constant to be searched dimensions.
From the above formula after it was found that inverted
enter the units take it to kg, m and s. To see the list above unit of force, obtained
The next example:
Given spring force equation
F = k Δ X
Where F is the spring force (Newton), Δ X is the length of the spring (meters) and k is the spring constant. Dimensional spring constant?
Further, .. next how to check whether or not an equation that connects certain quantities (check formula) with analysis of two-dimensional or a formula such as the following example:
1) The following equation linking the quantities on the motion of an object.
v t = v o + at
where v t is the velocity when t, v o is the initial velocity, a is acceleration and t is time.
Check with dimensional analysis of whether or not the above equation!
2) The position of an object is expressed in an equation
y = At 2 + Bt + C
with unit y in meters and t in second. A, B and C are constants. specify the units and dimensions of A, B and C! (Problem Fisikastudycenter)
Discussion
1) The dimensions on the left side:
v is the velocity t → m / s → L / T → LT -1
Dimension on the right:
v is the velocity o → m / s → L / T → LT -1
at is the acceleration x time → m / s 2 xs → m / s → L / T → LT -1
Seen left side dimension equal to the dimension on the right, so the above equation is right.
2) The assumption is that the quantities are added or subtracted have the same unit or dimension with the results. Of the equation
y = At 2 + Bt + C
Meter ... meter = ... + ... + ... meter meter
A constant unit determines
Results of combination units on the meter must At 2, enter other units that have been known in this case t (time) unit is s (second) so that
At 2 = m
As 2 = m
A = m / s 2
A dimension is LT -2
Determine the constants B unit
Bt also produces meter, enter the other unit which has been known to
Bt = m
Bs = m
B = m / s
Dimension of B is LT -1
Determine the constants C unit
C = m
Dimension C is L
Semester Question Bank Unit and Dimension 10 SMA (Indonesian)
Dimension of style?
Dimension of power?
Dimensions of energy?
Dimension of impulse?
Dimensions of momentum?
Assuming that some unknown formula X High School student, unless length (m), mass (kg), time (s), velocity (m / s), acceleration (m / s 2), wide (2 m) and volume ( m 3) are assumed to be known, following a decrease in the amount of Physics modest dimensions.
Here is the format:
Formula ---> Unit -> Dimension
and remember:
mass -> kg -> M (from M ass time ..!?! & do kliru M ether ..!)
length -> m -> L (L ength of time ...!?!)
time -> s -> T (from T ime time ...!)
Style
mass x acceleration -> (kg) (m / s 2) -> MLT - 2
Massa Type
mass / volume -> (kg) / (m 3) -> ML -3
Energy
mass x acceleration of gravity x height -> (kg) (m / s 2) (m) -> ML 2 T - 2
Pressure
force / area ---> (kg) (m / s 2) / m 2 -> ML -1 T -2
Business
force x displacement -> (kg) (m / s 2) (m) -> ML 2 T -2
Momentum
mass x velocity -> (kg) (m / s) -> MLT -1
Impulse
force x time interval -> (kg) (m / s 2) (s) -> MLT -1
Power
Effort / time -> (kg) (m / s 2) (m) / (s) -> ML 2 T -3
Weight
mass x acceleration due to gravity -> (kg) (m / s 2) -> MLT -2
Specific gravity
weight / volume -> (kg) (m / s 2) / (m 3) -> ML -2 T -2
Some have the same amount of dimensions, such as Enterprise and Energy, Style and weight, impulse and momentum.
For a slightly more complicated matter usually displayed formula, the brain-tweaking live, move left and right, up and down, insert the new unit is converted to a dimension.
Just a Sample:
Formula given the force of gravity between two objects as follows
by F is the force (Newton) m 1 and m 2 are the masses of the two pieces of the object (kg), r is the distance between the two objects (m) and G is a constant to be searched dimensions.
From the above formula after it was found that inverted
enter the units take it to kg, m and s. To see the list above unit of force, obtained
The next example:
Given spring force equation
F = k Δ X
Where F is the spring force (Newton), Δ X is the length of the spring (meters) and k is the spring constant. Dimensional spring constant?
Further, .. next how to check whether or not an equation that connects certain quantities (check formula) with analysis of two-dimensional or a formula such as the following example:
1) The following equation linking the quantities on the motion of an object.
v t = v o + at
where v t is the velocity when t, v o is the initial velocity, a is acceleration and t is time.
Check with dimensional analysis of whether or not the above equation!
2) The position of an object is expressed in an equation
y = At 2 + Bt + C
with unit y in meters and t in second. A, B and C are constants. specify the units and dimensions of A, B and C! (Problem Fisikastudycenter)
Discussion
1) The dimensions on the left side:
v is the velocity t → m / s → L / T → LT -1
Dimension on the right:
v is the velocity o → m / s → L / T → LT -1
at is the acceleration x time → m / s 2 xs → m / s → L / T → LT -1
Seen left side dimension equal to the dimension on the right, so the above equation is right.
2) The assumption is that the quantities are added or subtracted have the same unit or dimension with the results. Of the equation
y = At 2 + Bt + C
Meter ... meter = ... + ... + ... meter meter
A constant unit determines
Results of combination units on the meter must At 2, enter other units that have been known in this case t (time) unit is s (second) so that
At 2 = m
As 2 = m
A = m / s 2
A dimension is LT -2
Determine the constants B unit
Bt also produces meter, enter the other unit which has been known to
Bt = m
Bs = m
B = m / s
Dimension of B is LT -1
Determine the constants C unit
C = m
Dimension C is L
Semester Question Bank Unit and Dimension 10 SMA (Indonesian)
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